Two parallel plates having charges of equal magnitude but opposite sign are separated by 21.0 cm. Each plate has a surface charge density of 37.0 nC/m2. A proton is released from rest at the positive plate.

(a) Determine the potential difference between the plates. V

(b) Determine the kinetic energy of the proton when it reaches the negative plate. J

(c) Determine the speed of the proton just before it strikes the negative plate. km/s

(d) Determine the acceleration of the proton. m/s2 (towards the negative plate)

(e) Determine the force on the proton N (towards the negative plate.)

(f) From the force, find the magnitude of the electric field. kN/C Show that it is equal to that electric field found from the charge densities on the plates.

(Do this on paper. Your instructor may ask you to turn in this work.)