Question 3 (ca. 6 marks) For the initial value problem y+t y' y (2) = 2, (H) 2y-t' determine the maximal solution y(t) and its domain. Hint: The substitution z(t) = y(t)/t transforms (H) into a separable ODE. In order to see this, rewrite y' in terms of z. When solving the separable ODE, the formula 2az + b Ja dz = ln |az² + bz+c| + C may be helpful. az²+bx+c =