toilaphu23 toilaphu23
  • 03-06-2023
  • Mathematics
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Φ1 = ∬S1 (-2u^6cos(v) - 2u^3sin(v)) du dv
= ∫(0->1) ∫(0->2π) (-2u^6cos(v) - 2u^3sin(v)) dv du

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