A model for the population P(t) in a suburb of a large city is given by the initial-value problem dP = P(10-1 - 10-7P), P(0) = 3000, dt where t is measured in months. Find the population P of the suburb at time t. 106 P(t) = 1 + e -0.1t+5.806 X What is the limiting value of the population? 1000000 At what time will the population be equal to one-half of this limiting value? (Round your answer to one decimal place.) 58.06 months