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  • 01-01-2024
  • Chemistry
contestada

How many moles of Al are necessary to form 28.6 g of AlBr₃ from this reaction: 2Al(s)+3Br₂(l)→2AlBr₃ ​(s)?

a) 0.5 moles
b) 1.0 moles
c) 1.5 moles
d) 2.0 moles

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