If the DNA of E. coli is about 25% G and C and M. tuberculosis DNA is about 70% G and C,
which would be more likely to denature at a lower temperature?
side note:
(remember, A:T only has 2 hydrogen bonds, and G:C has three hydrogen bonds. Amount of
energy required corresponds to this)
a. It is not possible to determine with the given information.
b. M. tuburculosis
c. Both would denature at about the same rates.
d. E. coli