christiannecw christiannecw

03-02-2024
Chemistry

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3Ba(NO3)2 + Al2(SO4)3 = 3BaSO4 + 2Al(NO3)3.
How many grams of Al(NO3)3 can form when 200.0 mL of 0.500 M Al2(SO4)3 reacts with excess Ba(NO3)2.

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