anguie11ld anguie11ld
  • 04-03-2024
  • Mathematics
contestada

7.
5.2 cm
5.1 cm
3 cm
2 cm
Area of base, B:
× 3 =
Area of each large triangular face, T:
X
☐
Area of each small triangular face, t:
J-0
SA = 2(T + t) + B
SA=20
+
+
SA=
The surface area is
cm2.

7 52 cm 51 cm 3 cm 2 cm Area of base B 3 Area of each large triangular face T X Area of each small triangular face t J0 SA 2T t B SA20 SA The surface area is cm class=

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