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  • 05-04-2024
  • Mathematics
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Find a solution of the initial-value problem. y' = xy3 25 y(0) = 15 y = incorrect: your answer is incorrect.
a) y =e(x²/2)
b) y = 5e(x²/2)
c) y = 15e(x²/2)
d) y = 25e(x²/2)

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