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Calculate the following forces for a box with a mass=20.0 kg sitting on an incline of 29.0 degrees and a coefficient of friction which is 0.455. Calculate the parallel force, normal force, and frictional force.

Respuesta :

godrules1019
vertical force on the box=mg 
the component of gravity parallel=mg*SinTheta 
the component of gravity normal=mg*CosTheta 
frictional force up the plane: mg*cosTheta*mu max, but if it is sitting still, it is equal and opposite to mg*cosTheta (it cannot be greater than this or it would go up the plane).

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