[tex] 4n-3=75\\
4n=78\\
n=19.5\\\\
19.5 \not \in \mathbb{N} \implies \text{it's not}[/tex]
The nth term is given as 4n-3
If 75 a term of this sequence then 4n-3=75
Now we solve for n
To solve for n we add 3 both sides
4n-3+3=75+3
4n=78
To find n we divide by 4 both sides
78 is not divisible by 4 so n is not a whole number
n can not be a fraction
75 is not a term of the sequence
