The time required for one wing beat is 5 milliseconds.
Explanation
Lets assume, the time required for one wing beat is [tex]t[/tex] seconds
So, the time required for 200 wing beat [tex]= 200t[/tex] seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
[tex]200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds[/tex]
So, the time required for one wing beat is 5 milliseconds.
