Step 1
Find the circumference of the tire
[tex]C=2\pi r[/tex]
For r=0.30 m
Substitute
[tex]C=2*\pi*0.30[/tex]
[tex]C=1.88 meter[/tex]
Step 2
Find the approximate speed of Maria’s car
we know that
1 revolution of the tire is equal to the circumference
so
1 revolution is equal to 1.88 meter
then
779 revolutions per minute is equal to------> [tex]779*1.88=1,464.52\frac{meter}{min}[/tex]
convert to Km per hour
we know that
1 meter is equal to -------> 0.001 km
1 minute is equal to (1/60) hours
substitute
[tex]1,464.52\frac{meter}{min}=1,464.52*\frac{0.001}{(1/60)}\\\\=87.87 \frac{km}{hr} \\ \\ =88 \frac{km}{hr}[/tex]
therefore
the answer is
[tex]88 \frac{km}{hr}[/tex]
The relation between linear speed and angular speed is used. The approximate speed of Maria’s car is 88 kilometers per hour.
The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
If the radius of each tire on Maria’s car is 0.30 meters.
The instrument is showing 779 revolutions per minute.
We know that the angular speed will be given as
[tex]\omega = \dfrac{2\pi *779 }{60}\\\\\\\omega = 81.57668 \approx 81.58[/tex]
The relation between the linear speed and angular speed is given as
[tex]\rm v = r \omega \\\\v = 0.3 * 81.58\\\\v = 24.473*\dfrac{3600}{1000}\\\\ v = 88.1 \approx 88[/tex]
More about the speed link is given below.
https://brainly.com/question/7359669
