we are given
[tex] (6x^4-15x^3-2x^2-10x-4) [/tex] ÷ [tex] (3x^2+2) [/tex]
we can divide it by using long division method
we will get
[tex] Quotient=2x^2 -5x-2 [/tex]
[tex] Remainder=0 [/tex]
[tex] (6x^4-15x^3-2x^2-10x-4) [/tex] ÷ [tex] (3x^2+2) [/tex] = [tex] 2x^2 -5x-2 [/tex]
..............Answer
