Leg 1 is 13 - 1 (which is 12)
Leg 2 is 9 - 4 (which is 5)
We can use the Pythagorean theorem to solve for the distance (hypotenuse):
12^2 + 5^2 = c^2
144 + 25 = c^2
169 = c^2
c = [tex] \sqrt{169}[/tex]
c = 13
The distance is 13 units.
