isabel1423 isabel1423

03-10-2018
Mathematics

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What is the solution of the equation when solved over complex numbers? x^2+27=0

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quynhgiao911516nan quynhgiao911516nan

03-10-2018

[tex] {x}^{2} + 27 = 0 \\ {x}^{2} = - 27 \\ x = + - \sqrt{ - 27} \\ x = + - \sqrt{27 \times ( - 1) } [/tex]
[tex]x = + - 3 \sqrt{3} \times \sqrt{ - 1} [/tex]
[tex]x = + - 3 \sqrt{3} i[/tex]

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