The length of a rectangular garden is 7 feet longer than its width. The garden's perimeter is 186 feet. Find the width of the garden.

Respuesta :

We have a rectangular garden. The length of the garden is 7 feet longer than its width.

Lets say the width of the garden is 'x' feet. So, the length of the garden must be [tex](x+7)[/tex] feet.

Length [tex]=(x+7)[/tex] feet

Width [tex]=x[/tex] feet

We have been given that the perimeter of the garden is 186 feet.

Now as we know that the perimeter of the rectangle is:

[tex]2(length+width)[/tex]

Plugging the values of length and width in the equation, we get:

Perimeter [tex]= 2((x+7)+x)=2(2x+7)=4x+14[/tex]

We know that perimeter of the garden is equal to 186 feet,

So,

[tex]186=4x+14[/tex]

Solving for 'x' we get:

[tex]4x+14=186[/tex]

[tex]4x=186-14=172[/tex]

[tex]x=\frac{172}{4} =43[/tex]

We had assumed that the width of the garden is 'x' feet and now that we have the value of 'x'. We can say that:

The width of the rectangular garden is 43 feet.


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