asialmonroeov1rz4 asialmonroeov1rz4

04-10-2018
Mathematics

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a line is perpendicular to y=x/3-2 and passes through point( 6,2) write its equation

Respuesta :

vtorres61 vtorres61

04-10-2018

First find slope of perpendicular:

M=1/3, so new slope m= -3

y=mx + b, and subsitute (6,2) and m

2=-3(6) + b, move -18 to other side

b=20

y = -3x+20

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