Answer is:
the mass of a sample of aluminum is 9.45 grams.
ΔT = 100.1°C - 30.0°C.
ΔT = 70.1°C.; change in temperature of a sample of aluminium.
Cp(Al) = 0.900 J/g·°C; specific heat capacity for aluminium.
Q = 596 J; heat absorbed.
Q = m(Al) · ΔT · Cp(Al).
m(Al) = Q ÷ (ΔT · Cp(Al)).
m(Al) = 596 J ÷ (70.1°C · 0.900 J/g·°C).
m(Al) = 9.45 g; mass of aluminium sample.
