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Given the equation 2 CO + O2 —> 2CO2, how many grams of CO2 form if 34.0 grams of CO are combined with excess oxygen?

a) 53.4
b) 21.6
c) 145
d) 107

This question is really confusing to me, and I’m not even sure how to go about answering it.

Respuesta :

2270300019

firstly we need to calculate the number of moles of 34.0 g CO.

mole = mass/relative molecular mass = 34/(12+16) = 1.214 mol

CO : CO2 = 2 : 2 = 1 : 1

so that number of moles of CO2 = number of moles of CO = 1.21 mol

then use the number of moles to calculate the mass

mass = mole * relative molecular mass = 1.21 * 44 = 53.4 g

so choose A


CintiaSalazar

Taking into account the reaction stoichiometry,  the correct answer is option a): 53.4 grams of CO₂ form if 34.0 grams of CO are combined with excess oxygen.

The balanced reaction is:

2 CO + O₂ → 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO: 2 moles
  • Oâ‚‚: 1 mole
  • COâ‚‚: 2 moles

The molar mass of the compounds is:

  • CO: 28 g/mole
  • Oâ‚‚: 32 g/mole
  • COâ‚‚: 44 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CO: 2 moles× 28 g/mole= 56 grams
  • Oâ‚‚: 1 mole× 32 g/mole= 32 grams
  • COâ‚‚: 2 moles× 44 g/mole= 88 grams

Then you can apply the following rule of three: if by stoichiometry 56 grams of CO produce 88 grams of COâ‚‚, 34 grams of CO produce how much mass of COâ‚‚?

[tex]mass of CO_{2} =\frac{34 grams of COx88 grams of CO_{2} }{56 grams of CO}[/tex]

mass of COâ‚‚=53.4 grams

Finally, the correct answer is option a): 53.4 grams of COâ‚‚ form if 34.0 grams of CO are combined with excess oxygen.

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