Respuesta :

f(x) = |x-4|-3

turning point is at x=4

for x<4, f(x) = -(x-4)-3 w a -ve slope

x=4, f(x)=-3

for x>4, f(x)= (x-4)-3 w a +ve slope

so answer is C

|x-4| is absolute function

the function changes sign from negative to positive at x goes from <4 to >4

and at x=4, it is equal to 0

so f(4)=0-3=-3

The right graph is C.


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