[tex]y = {x}^{3} - 4 {x}^{2} - 45x \\ y = x( {x}^{2} - 4x - 45) \\ y = x(x + 5)(x - 9) \\ x = 0, - 5,9[/tex]
So, to find our x-intercepts, y must be zero
[tex]0 = x \\ \\ 0 = (x + 5) \\ - 5 = x \\ \\ 0 = (x - 9) \\ 9 = x[/tex]
ANSWER: (0,0) (-5.0) (9,0) are your x-intercepts
