Answer:
f(x) = 7 is an even function.
Step-by-step explanation:
Any function is even when [tex]f(x) = f(-x)[/tex] and gives a graph that is symmetric with respect to the y-axis.
We are given these options and we have to check whether which of them is an even function:
[tex]f(x)= (x-1)^2[/tex] [tex]= x^2-2x+1[/tex]
and [tex]f(-x) = (-x - 1)^2 = x^2 + 2x + 1[/tex] - This function is not even
[tex]f(x) = 8x[/tex]
and [tex]f(-x) = -8x[/tex] - This function is not even
[tex]f(x)=x^2-x[/tex]
and [tex]f(-x) = (-x)^2 + x = x² + x[/tex] - This function is not even
[tex]f(x) = 7[/tex]
and [tex]f(-x) = 7[/tex] - EVEN FUNCTION
We get the same value for [tex]f(x)[/tex] and [tex]f(-x)[/tex], therefore f(x) = 7 is an even function.
