Respuesta :
[tex]\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies \cfrac{5}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=\cfrac{5}{4}(x-4) \\\\\\ y+6=\cfrac{5}{4}x-5\implies y=\cfrac{5}{4}x-11[/tex]
