AsiaLilJT AsiaLilJT
  • 04-11-2018
  • Mathematics
contestada

Please help with #14

Please help with 14 class=

Respuesta :

Thisguy248 Thisguy248
  • 09-11-2018

h(t)=(t-1)^2-(t+1)^2

0=(t-1)^2-(t+1)^2

(t+1)^2=(t-1)^2

t^2+2t+1=t^2-2t+1

2t+1=-2t+1

4t+1=1

4t=0

t=0

There is one zero at t=0

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