Hence, the values of unknowns A,B and C are:
A=16
B=64
C=256
We are given a recursive defined geometric sequence f(x+1)=4(f(x))
X f(x)
1 4
2 A
3 B
4 C
5 1,024
When x=1,
we have f(x)=4.
when so,
f(2)=4f(1)=4×4=16.
Hence, when x=2 f(x)=16=A.
Similarly,
f(3)=4×f(2)
f(3)=4×16=64
Hence, when x=3 f(x)=64=B.
Similarly,
f(4)=4×f(3)=4×64=256
i..e when x=4 f(x)=256=C.
similarly,
f(5)=4×f(4)=4×256=1024
when x=5 f(x)=1024
Hence, the values of unknowns A,B and C are:
A=16
B=64
C=256
