Answer: [tex]-\frac{2}{3x+1}[/tex]
Step-by-step explanation:
[tex]\frac{-x-2}{9x^{2}-1}[/tex] + [tex]\frac{-5x+4}{9x^{2}-1}[/tex]
= [tex]\frac{-x-2-5x+4}{9x^{2}-1}[/tex]
= [tex]\frac{-6x+2}{9x^{2}-1}[/tex]
= [tex]\frac{-2(3x-1)}{(3x-1)(3x+1)}[/tex]
= [tex]\frac{-2}{3x+1}[/tex]
