Respuesta :
The triangle is inside the circle with the vertices of the triangle on the circle - since the center of the circle is on the hypotenuse, the hypotenuse is the diameter(D) of the circle
:
D = 120 feet
:
circumference of the circle = 22/7 * 120 = 377.14 feet
perimeter of triangle = 120 + 60 + 103.92 = 283.92
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1) total distance around circle + triangle = 661.06 feet
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2) the vertices of the triangular central area must lie on the
circular pool - construct perpendicular bisectors of two sides
of the triangular area, where they intersect is the center of
the circular pool, the distance from the center to any one of
the vertices of the triangular area is the radius of the
circular pool
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3) the intersection of the angle bisectors of the triangular area
is the center of the shark tank
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4) volume of pool = ((pi * 60^2) - area of triangle) * 4 =
(11314.285) - (1/2 * 103.92 * 60) * 4 = 32786.74 cubic feet
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5) 8196.685 * x < 30000
x < 3.66 feet
average depth must be less than 3.66 feet
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Given that the :
Sides of the triangle are : 60 feet, 120 feet and 103.92 feet.
The hypotenuse of the right triangle is also the diameter of the circle as the vertices of the triangle lies on the circumference of the circle.
So the diameter of the circle is 120 feet.
And thus the radius (r) of the circle is = [tex]$\frac{120}{2}$[/tex]
= 60 feet
1. Therefore the circumference of the circular swimming pool is = 2πr
= 2 x 3.14 x 60
= 376.8 feet
Thus, the length of the gold leaf cover in terms of linear feet is 376.8 feet.
2. The largest area of the pool is the semi circle of the pool where the owner can built a waterslide.
3. The mid point of the hypotenuse of the triangular resort is the center of the circular pool.
So, the center point of the concentric circular fish tank is the center point of the circular pool or the center point of the hypotenuse of the triangular resort.
4. Given the depth (h) of the pool is = 4 feet
Volume of the circular pool is given as : [tex]$\pi r^2 h$[/tex]
= [tex]$3.14 \times (60)^2 \times 4$[/tex]
= 45,216
Therefore, the pool can be filled with 45,216 cubic foot of water.
5. Given threshold volume of the pool = 40,000 cubic foot
So the new depth of the pool can be calculated as :
[tex]$40,000 = \pi r^2 h$[/tex]
[tex]$40,000 = 3.14 \times 60^2 \times h$[/tex]
[tex]$h=\frac{40,000}{3.14 \times 3600}$[/tex]
h = 3.53 feet
Therefore, the maximum depth of the pool now can be 3.53 feet.
6. if the average depth is 4 feet.
Then the volume of water is = 45,216 cubic feet
When the depth is 3.53 feet, then the volume of water is = 40,000 cubic feet
So the difference in water is : 45,216 - 40,000
= 5,216 cubic feet
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