kaykayreynolds123 kaykayreynolds123

04-12-2018
Chemistry

contestada

what is the [oh-] in a solution with a poh of 11.25

Respuesta :

kenmyna kenmyna

13-12-2018

The [Oh-] in the solution with a POh of 11.25 is 5.623 x 10^-12 M

calculation

POH= - log [ OH-]

Therefore - log [oH-] =11.25

To calculate [oh-] concentration find the antilog of 11.35

= 10^- 11.25 = 5.623 x 10^-12 M

Answer Link

landondowell landondowell

13-04-2021

Answer:

5.62*10^-12

Explanation:

Acellus

Answer Link

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