Match the reasons with the statements in the proof to prove that BC = EF, given that triangles ABC and DEF are right triangles by definition, AB = DE, and A = D.

Given:

ABC and DEF are right triangles

AB = DE

A = D

Prove:

BC = EF

1. ABC and DEF are right triangles

AB = DE

A = D CPCTE (Corresponding Parts of Congruent Triangles are Equal)

2. ABC ≅ DEF Given

3. BC = EF LA (Leg - Angle)

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parmesanchilliwack parmesanchilliwack · Answer 1 · 2018-12-17T06:51:46+01:00

Answer: Statement Reason

1. ABC and DEF are right triangles 1. Given

AB = DE , ∠A = ∠D

2. Δ ABC ≅ Δ DEF 2. LA(Leg - Angle)

3. BC = EF 3. CPCTE(Corresponding

Parts of Congruent

Triangles are Equal)

Step-by-step explanation:

Here, Given: ABC and DEF are right triangles.

AB = DE and ∠A = ∠D

Prove: BC = EF

Since, AB = DE and ∠A = ∠D

That is, leg and an acute angle of right triangle ABC are congruent to the corresponding leg and acute angle of right triangle DEF,

Therefore, By Leg angle theorem,

Δ ABC ≅ Δ DEF

⇒ BC ≅ EF ( by CPCTC )

⇒ BC= EF

httpjoohoney63 httpjoohoney63 · Answer 2 · 2021-11-21T17:43:10+01:00

Answer:

Statement Reason

1. ABC and DEF are right triangles 1. Given

AB = DE , ∠A = ∠D

2. Δ ABC ≅ Δ DEF 2. LA(Leg - Angle)

3. BC = EF 3. CPCTE(Corresponding

Parts of Congruent

Triangles are Equal)

Step-by-step explanation: