Answer:
The reaction requires 243 grams of HF.
Explanation:
[tex]SiO_2 + 4HF\rightarrow SiF_4 + 2H_2O[/tex]
Moles of silicon dioxide =[tex]\frac{182 g}{60 g/mol}=3.033 mol[/tex]
According to reaction 1 moles of silicon dioxide reacts with 4 moles of  hydrogen fluoride.
Then 3.033 moles of silicon dioxide will react with:
[tex]\frac{4}{1}\times 3.033 mol=12.133 mol [/tex] of hydrogen fluoride
Mass of 12.133 moles of hydrogen fkluorode is:
[tex]12.133 mol\times 20 g/mol=242.66 g\approx 243 g[/tex]
The reaction requires 243 grams of HF.
