Hello from MrBillDoesMath!
Answer: -3 and 2
Discussion:
The equation to solve is:
6/m + 2 = (m+3)/(m-1)
Multiple both sides by m * (m-1).
6/m * (m*(m-1)) + 2 m (m-1) = (m+3)/(m-1) * (m(m-1))
Simplify:
6 (m-1) + 2 m (m-1) = (m+3)*m =>
6m -6 + 2m^2 - 2m = m^2 + 3m =>
2m^2 +4m - 6 = m^2 + 3m. Subtract m^2 and 3m from both sides
m^2 + m - 6 = 0. Factor this equation.
(m +3) ( m-2) = 0 so the solution set is -3 and 2
Thank you,
MrB
