let Coefficients of Friction of Rubber on asphalt (dry) =0.7
F= Coefficients of Friction * normal force = 0.7 * 60 =42 N
so the net force of the rubber is zero, meaning it will travel at a constant speed.
When the rubber is travel at 2m/s, 42N is required to keep moving at constant speed
Answer:
F = 40.2 N
Explanation:
Weight of the rubber block, W = 60 N
If m is the mass of the rubber block,
[tex]m=\dfrac{W}{g}[/tex]
[tex]m=\dfrac{60\ N}{9.8\ m/s^2}[/tex]
m = 6.12 kg
We know that the coefficient of friction between rubber block and dry asphalt is, [tex]\mu_k=0.67[/tex]
The relation between the coefficient of friction and the force is given by :
[tex]F=\mu_k N[/tex]
Here, N = W
[tex]F=\mu_k W[/tex]
[tex]F=0.67\times 60\ N[/tex]
F = 40.2 N
So, the magnitude of force needed to keep a 60 newton rubber block moving across level,dry asphalt in a straight line is 40.2 N. Hence, this is the required solution.
