Answer:
The vehicle's acceleration is -4.20 m/s/s
Explanation:
(acceleration m/s/s) = (change in velocity m/s) / (change in time s)
(acceleration) = (2.0-14.0 m/s) / (2.86 s) = - 4.20 m/s/s
The acceleration is -4.20 meters per second squared. The negative sign indicates the vehicle is decelerating (slowing down).
When a vehicle slows from 14 m/s west to 2.0 m/s west in 2.86 seconds, the acceleration of the vehicle would be - 4.196 m/s²
The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
The slope of the velocity time curve represents the acceleration of the object
By using newton's first equation of the motion for the vehicle
v= u + at
As given in the problem a vehicle slows from 14 m/s west to 2.0 m/s west in 2.86 seconds.
u = 14 meters/second , v = 2 meters/second and t = 2.86 seconds
By substituting the respective values in newton's first equation
2 = 14 + a×2.86
a = -12 /2.86
a = -4.196 m/s²
In other words, one can a vehicle deaccelerates at the rate of 4.196 m/s²
Thus, A vehicle's acceleration would be -4.161 m/s² if it slowed from 14 m/s west to 2.0 m/s west in 2.86 seconds.
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