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To begin the experiment, 1.5g of methane CH4 is burned in a bomb calorimeter containing 1,000 grams of water. The initial temperature of water is 25°C. The specific heat of water is 4.184 J/g°C. The heat capacity of the calorimeter is 695 J/°C . After the reaction the final temperature of the water is 37°C.

Using the formula qcal =Ccal ‱ ΔT,calculate the heat absorbed by the calorimeter. Show work.

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Answer:

The calorimeter absorbs 8.3 kJ.

Step-by-step explanation:

The formula for the heat q absorbed by the calorimeter is

q = CcalΔT

Data:

Ccal = 695 J/°C

T₁ = 25 °C; T₂ = 37 °C

Calculations:

ΔT = T₂ - T₁

ΔT = 37 - 25

ΔT = 12 °C

q = 695 × 12  

q = 8300 J

q = 8.3 kJ

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