contestada

A uniformly charged rod (length = 2.0 m, charge per unit length = 5.0 nc/m) is bent to form one quadrant of a circle. what is the magnitude of the electric field at the center of the circle?

Respuesta :

Electric field at the center of circular arc is given by the formula

[tex]E = \frac{2k\lambda sin\frac{\theta}{2}}{R}[/tex]

here we know that

[tex]\lambda = 5nC/m[/tex]

[tex]k = 9 \times 10^9 Nm^2/C^2[/tex]

[tex]\frac{\pi}{2}R = L = 2m[/tex]

[tex]R = \frac{4}{\pi}[/tex]

also we know that

[tex]\theta = \frac{\pi}{2}[/tex]

now from above formula

[tex]E = \frac{2(9\times 10^{-9})(5\times 10^{-9})sin45}{4/\pi}[/tex]

[tex]E = 50 N/C[/tex]