Respuesta :
Use conservation of momentum ;
m1u1 + m2u2 = m1v1 + m2v2
1200×15.6 + 0 = 2700v
v = 18720/2700
v = 6.933 or ~ 7 m/s
m1u1 + m2u2 = m1v1 + m2v2
1200×15.6 + 0 = 2700v
v = 18720/2700
v = 6.933 or ~ 7 m/s
We have that for the Question "A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together,"
it can be said that their combined velocity immediately after the collision is
- v=6.9m/s
From the question we are told
A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, what is their combined velocity immediately after the collision?
Generally the equation for the conservation momentum is mathematically
given as
[tex]m_1v_1+m_2v=(m_1+m_2)(v)\\\\1200*15.6+1500*0=1200+1500*v[/tex]
v=6.9m/s
Therefore
their combined velocity immediately after the collision is
v=6.9m/s
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