A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, what is their combined velocity immediately after the collision?

Respuesta :

Use conservation of momentum ;

m1u1 + m2u2 = m1v1 + m2v2

1200×15.6 + 0 = 2700v

v = 18720/2700

v = 6.933 or ~ 7 m/s

We have that for the Question "A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together,"

it can be said that their combined velocity immediately after the collision is

  • v=6.9m/s

From the question we are told

A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, what is their combined velocity immediately after the collision?

Generally the equation for the conservation momentum  is mathematically

given as

[tex]m_1v_1+m_2v=(m_1+m_2)(v)\\\\1200*15.6+1500*0=1200+1500*v[/tex]

v=6.9m/s

Therefore

their combined velocity immediately after the collision is

v=6.9m/s

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