Respuesta :
Answer:∠JML ≅ ∠QJM
Alternate Interior Angles Theorem   Â
Step-by-step explanation:
Here, Given: JKML is a parallelogram,
That is, JK â•‘ ML and JM â•‘ KL
Prove: ∠MLK ≅ ∠KJM and ∠JML ≅ ∠LKJ
Extend segment JM beyond point  and draw point P (Construction)
∠MLK ≅ ∠PML              ( Alternate Interior Angles Theorem)
∠PML ≅ ∠KJM               (  Corresponding Angles Theorem )
⇒ ∠MLK ≅ ∠KJM             ( By transitive property of equality )
Extend segment JK beyond point J and draw point Q, by Construction.
∠JML ≅ ∠QJM                ( Alternate Interior Angles Theorem)
∠QJM ≅ ∠LKJ               (  Corresponding Angles Theorem )
⇒ ∠JML ≅ ∠LKJ              ( By transitive property of equality )
Thus, the opposite angles of parallelogram JKLM are congruent.
Answer:
∠JML ≅ ∠QJM
Alternate Interior Angles Theorem
Step-by-step explanation: