[tex](2x + 4y = 14) \div 2 = x + 2y = 7[/tex]
making x the subject
[tex]x = 7 - 2y[/tex]
substitute into second equation
[tex]3(7 - 2y) + 12y = 51[/tex]
by solving, y=5
substitute into first equation
[tex]2x + 4(5) = 14[/tex]
by solving, x=-3
Therefore the ordered pair is (-3,5)
