A circular pool with a 10 foot diameter is surrounded by a deck. What is the area of the deck which surrounds the pool? use 3.14
Answer:
146.5 sq. feet.
Step-by-step explanation:
Area of the deck = Large Square (with 15 ft side) - Circular Pool (with radius 10/2=5)
Large Square area = [tex]s^2=(15)^2=225[/tex]
Circular Pool area = [tex]\pi r^2=\pi (5)^2=\pi (25)\\=25(3.14)\\=78.5[/tex]
Thus, area of deck surrounding pool = [tex]225-78.5=146.5[/tex] sq. feet
ANSWER
[tex]146.5 {ft}^{2} [/tex]
EXPLANATION
The circular pool has diameter,
[tex]d = 10ft[/tex]
This means the radius is;
[tex]r = \frac{10}{2} = 5ft[/tex]
The area of the pool is
[tex] = \pi \: {r}^{2} [/tex]
[tex] =(3.14) \times {5}^{2} [/tex]
[tex] = 78.5[/tex]
The area of the deck is equal to the area of the square minus area of circular pool.
[tex] {15}^{2} - 78.5 = 146.5 {ft}^{2} [/tex]