Respuesta :

Answer:

146.5 sq. feet.

Step-by-step explanation:

Area of the deck = Large Square (with 15 ft side) - Circular Pool (with radius 10/2=5)

Large Square area = [tex]s^2=(15)^2=225[/tex]

Circular Pool area = [tex]\pi r^2=\pi (5)^2=\pi (25)\\=25(3.14)\\=78.5[/tex]

Thus, area of deck surrounding pool = [tex]225-78.5=146.5[/tex] sq. feet

ANSWER

[tex]146.5 {ft}^{2} [/tex]

EXPLANATION

The circular pool has diameter,

[tex]d = 10ft[/tex]

This means the radius is;

[tex]r = \frac{10}{2} = 5ft[/tex]

The area of the pool is

[tex] = \pi \: {r}^{2} [/tex]

[tex] =(3.14) \times {5}^{2} [/tex]

[tex] = 78.5[/tex]

The area of the deck is equal to the area of the square minus area of circular pool.

[tex] {15}^{2} - 78.5 = 146.5 {ft}^{2} [/tex]