efrenlugo13 efrenlugo13
  • 05-03-2019
  • Mathematics
contestada

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

Respuesta :

zrh2sfo
zrh2sfo zrh2sfo
  • 05-03-2019

Answer:

(5, -6)

Step-by-step explanation:

Answer Link
Anonymouslizard
Anonymouslizard Anonymouslizard
  • 06-03-2019

Answer:

Step-by-step explanation:

The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is

[tex]x=\sqrt{(-y-10)(y+2)} +5,-\sqrt{(-y-10)(y+2)} +5[/tex]

Steps:

(x-5)²+(y+6)²=4²

Rewrite:

(x-5)²+(y-(-6))²=4²

Answer Link

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