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You are designing a pendulum clock to have a period of 1.0 s. The acceleration of gravity is 9.81 m/s2 . How long should the pendulum be? Answer in units of m.

Respuesta :

skyluke89

Answer:

0.25 m

Explanation:

The period of a pendulum is given by

[tex]T=2 \pi \sqrt{\frac{L}{g}}[/tex]

where  in this case

T = 1.0 s is the period of the pendulum

g = 9.81 m/s^2 is the acceleration due to gravity

L is the length of the pendulum

Re-arranging the equation and solivng for L, we find the length of the pendulum:

[tex]L=g (\frac{T}{2 \pi})^2=(9.81 m/s^2)(\frac{1.0 s}{2\pi})^2=0.25 m[/tex]

Answer:

.248490m

Explanation:

Using the equation:

T=Time

L=Length

g=Gravitational Force≈9.81

T= [tex]2\pi \sqrt{L/g}[/tex] or easier written to find the length using time: [tex]L=\frac{T^{2} *g}{4\pi^{2} }[/tex]

so simply plugging in 1 for T we get [tex]\frac{9.81}{4\pi^{2} } \\[/tex]≈.25m

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