Answer:
[tex]-\frac{3a^{11}}{4r^{3}}[/tex]
Step-by-step explanation:
If we move a up to the numerator, the - power becomes a + power, so we add the two to get [tex]a^{11}[/tex]. If we do the same to r but move it to the bottom, it becomes [tex]r^{3}[/tex].
