Answer:
The area of the resulting cross section is [tex]78.5\ m^{2}[/tex]
Step-by-step explanation:
we know that
The resulting cross section is a circle congruent with the circle of the base of cylinder
therefore
The area is equal to
[tex]A=\pi r^{2}[/tex]
we have
[tex]\pi=3.14[/tex]
[tex]r=10/2=5\ m[/tex] -----> the radius is half the diameter
substitute the values
[tex]A=(3.14)(5)^{2}=78.5\ m^{2}[/tex]
