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The length of a rectangle is shown below:

If the area of the rectangle to be drawn is 10 square units, where should points C and D be located, if they lie vertically below the line that connects B and A, to make this rectangle?

C(-1, 1), D(1,1)
C(-1, -2), D(1,-2)
C(-1, 5), D(1, 5)
C(-1, -7), D(1, -7)

The length of a rectangle is shown below If the area of the rectangle to be drawn is 10 square units where should points C and D be located if they lie vertical class=

Respuesta :

carlosego

Answer: Second option.

Step-by-step explanation:

As you can see in the graph attached, the lenght of the side AB is 2 units.

The formula for calculate the area of  rectangle is:

[tex]A=l*w[/tex]

Where l is the length and w is the width.

Therefore, if the area of the rectangle to be drawn is 10 square units and you know AB=2 units and CD  lies vertically below BA , then you can solve for the length:

[tex](10units^2)=(2units)l\\l=5units[/tex]

Therefore C and D are located at:

[tex]C=B(-1, 3-5)=> C(-1,-2)[/tex]

[tex]D=A(1, 3-5)=> D(1,-2)[/tex]

imlittlestar

Answer:

The correct answer is,

Option 2).  C(-1, -2), D(1,-2)

Step-by-step explanation:

It is given that,If the area of the rectangle to be drawn is 10 square units

To find the length of rectangle

From the figure we get length of AB = 2 units

Therefore Area = length * breadth = 10

Therefore length = 10/2 = 5 units

To find the points of C and D

we have B(-1, 3)

The point C is 5 units below the point B

Therefore C(-1, 3-5) = C(-1,-2)

we have A(1, 3)

The point D is 5 units below the point B

Therefore D(1, 3-5) = A(1,-2)

Therefore the correct answer is option 2

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