Answer:
no real solutions
Step-by-step explanation:
For a quadratic in standard form : y = ax² + bx + c : a ≠ 0
The value of the discriminant
Δ = b² - 4ac informs about the nature of the solutions
• If b² - 4ac > 0 then 2 real and distinct solutions
• If b² - 4ac = 0 then 2 real equal solutions
• If b² - 4ac < 0 then no real solutions
For y = 3x² + 7x + 6
with a = 3, b = 7, c = 6, then
b² - 4ac = 7² - (4 × 3 × 6) = 49 - 72 = - 23
Since b² - 4ac < 0 the equation has no real solutions
