How many moles of tungsten atoms are in 4.8 x10^25?

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superman1987 superman1987 · Answer 1 · 2019-06-10T23:11:54+02:00

Answer:

79.7 mol.

Explanation:

It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

Using cross multiplication:

1.0 mole of tungsten contains → 6.022 x 10²³ atoms.

??? mole of tungsten contains → 4.8 x 10²⁵ atoms.

∴ The no. of moles of tungsten contains (4.8 x 10²⁵ atoms) = (1.0 mol)(4.8 x 10²⁵ atoms)/(6.022 x 10²³ atoms) = 79.7 mol.

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abidemiokin abidemiokin · Answer 2 · 2021-11-15T12:43:52+01:00

There are 79.7 moles of tungsten atoms in [tex]4.8 \times 10^{25}[/tex]

Given the following parameter:

Moles of tungsten = [tex]4.8 \times 10^{25}atoms[/tex]

It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms. Hence:

1 mole = 6.022 x 10²³atoms

x = 4.8 x 10²⁵ atoms

Cross multiply:

6.022 × 10²³x = 4.8 x 10²⁵

x = 4.8 x 10²⁵/6.022 × 10²³

x = 0.797×10²

x = 79.7 moles

This shows that there are 79.7 moles of tungsten atoms in [tex]4.8 \times 10^{25}[/tex]

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