Explanation:
It is given that,
Mass of concrete pilling, m = 50 kg
Diameter of wire, d = 1 mm
Radius of wire, r = 0.0005 m
Length of wire, L = 11.2
Young modulus of steel, [tex]Y=20\times 10^{10}\ N/m^2[/tex]
The young modulus of a wire is given by :
[tex]Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta L}{L}}[/tex]
[tex]Y=\dfrac{F.L}{A\Delta L}[/tex]
[tex]\Delta L=\dfrac{F.L}{A.Y}[/tex]
[tex]\Delta L=\dfrac{50\ kg\times 9.8\ m/s^2\times 11.2\ m}{\pi (0.0005\ m)^2\times 20\times 10^{10}\ N/m^2}[/tex]
[tex]\Delta L=0.034\ m[/tex]
So, the wire will stretch 0.034 meters. Hence, this is the required solution.
