Answer:
b = 1084.5 kg/s
Explanation:
As we know that the amplitude of damped oscillation is given as
[tex]A = A_o e^{-\frac{bt}{2m}}[/tex]
here we know that
[tex]A = \frac{A_o}{2}[/tex]
after time t = 4.9 minutes
also we know that
[tex]m = 2.30 \times 10^5 kg[/tex]
now we will have
[tex]\frac{A_o}{2} = A_o e^{-\frac{bt}{2m}}[/tex]
[tex]\frac{bt}{2m} = ln2[/tex]
[tex]b = \frac{ln2 (2m)}{t}[/tex]
[tex]b = \frac{2(ln2)(2.30 \times 10^5)}{4.9 \times 60}[/tex]
[tex]b = 1084.5 kg/s[/tex]
