Respuesta :
Answer : The molar volume of the solution is, [tex]24m^3/mole[/tex]
Explanation : Given,
Partial molar volumes of component A = [tex]30m^3/mole[/tex]
Partial molar volumes of component B = [tex]20m^3/mole[/tex]
Mole fraction of component A = 0.4
First we have to calculate the mole fraction of component B.
As we know that,
[tex]\text{Mole fraction of component A}+\text{Mole fraction of component B}=1[/tex]
[tex]\text{Mole fraction of component B}=1-0.4=0.6[/tex]
Now we have to calculate the molar volume of the solution.
Expression used :
[tex]V_s=X_A\times \bar V_A+X_B\times \bar V_B[/tex]
where,
[tex]\bar V_A[/tex] = partial molar volumes of component A
[tex]\bar V_B[/tex] = partial molar volumes of component B
[tex]V_s[/tex] = molar volume of the solution
[tex]X_A[/tex] = mole fraction of of component A
[tex]X_B[/tex] = mole fraction of of component B
Now put all the give values in the above expression, we get:
[tex]V_s=0.4\times 30m^3/mole+0.6\times 20m^3/mole[/tex]
[tex]V_s=24m^3/mole[/tex]
Therefore, the molar volume of the solution is, [tex]24m^3/mole[/tex]
